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Green circuit board with USB-C connector and five SATA ports

Vszerda

Vszerda USB-C to 5-Port SATA 3.0 Adapter Card JM575+JMS580

SKU CH-NPAJ-H2SWG

Connects five SATA 3.0 drives via a single USB-C port using JM575 and JMS580 chips

  • Add five SATA drives through one USB-C connection using JM575 and JMS580 controllers
  • Each port delivers SATA 3.0 6Gbps bandwidth for fast data access
  • Expand storage capacity without opening the computer case
  • Plug-and-play design works with standard SATA hard drives and SSDs

Five-Port SATA 3.0 Expansion via USB-C

This adapter adds five SATA 3.0 ports to a system through a single USB-C connection. It uses JM575 and JMS580 bridge chips to expose each attached drive to the host. The card suits builders who need to connect multiple hard drives or solid-state drives without opening the case or using internal ports.

Bandwidth shared across five drives at 6 Gbps

The USB-C link caps aggregate throughput at the interface maximum, so five active drives divide the available 6 Gbps bandwidth. Sustained transfers on several drives at once will be slower than a direct motherboard SATA connection. Builders who need full 6 Gbps per drive simultaneously should consider an internal controller instead.

Highlights

  • Add five SATA drives through one USB-C connection using JM575 and JMS580 controllers
  • Each port delivers SATA 3.0 6Gbps bandwidth for fast data access
  • Expand storage capacity without opening the computer case
  • Plug-and-play design works with standard SATA hard drives and SSDs

Specifications

No published specifications for this item yet.

Questions about this item

Should I pick the JM575 or JMS580 chipset version?

This card uses both chips together — JM575 handles the USB-C link and JMS580 splits it to five SATA ports, so there is no separate version to choose.

Will the 6 Gbps SATA rate be fully available on each of the five ports?

The 6 Gbps figure is the USB-C host link speed; the five SATA ports share that bandwidth, so simultaneous drives will split the throughput.

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